在C語(yǔ)言中，語(yǔ)言求求矩陣的矩陣逆通常使用高斯約當消??元法（Gauss( ?ω?)Jordan Elimina?tion）或者伴隨矩陣法（Adjoint Meth??od），這里我們主要介紹高斯約當消元法。語(yǔ)言求
（圖片來(lái)源網(wǎng)絡(luò )，矩陣侵刪）1、矩陣將原矩陣A復制到一個(gè)新的語(yǔ)言求矩陣B中，對B進(jìn)行行變換，矩陣使得B的語(yǔ)言求主對角線(xiàn)上的元素為1，其他元素為0。矩陣
2、語(yǔ)言求計算B的矩陣轉置矩陣BT。
3、語(yǔ)言求計算BT與B的乘積，即BT * B。
4、計算BT * B的逆矩陣，即(BT * B)^(1)。
6、返回結果。
下面是一個(gè)簡(jiǎn)單的C語(yǔ)言實(shí)現：??
#include <??;stdio.h>#include <stdlib.h>#include <math.h>voi(′_ゝ`)d swap_rows(double **matrix, int row1, int row2, int col) { fo??r (int i = 0; i < col; i++) { double?? temp = matrix[row1][i]; matrix[row1]??[i] = matrix[row2][i]; matrix[row2][i] = temp; }}void gauss_jordan_elimination(double **matrix(╯°□°)╯, in┐(′д｀)┌t rows, int cols) { for (int i = 0; i <ヽ(′▽?zhuān)?ノ; rows; i++) { // Find the maximum element in the?? current colu???mn and its roヾ(′▽?zhuān)??w index int max_row = i; for (i(′?｀*)nt k = i + 1; k < rows; k++) { ifヾ(′▽?zhuān)?? (fabs(matrix[k][i]) > fabs(matrix[max_row][i])) { max_row = k; } } // Swap the current row with the row containing the maximum element swap_rows(matrix, i, max_row, cols); // Make the diagonal element 1 by dividing other elements?? in the current row for (int k = i + 1; k <?? rows; k++) { double factor = ma(′▽?zhuān)?trix[k][i]ヽ(′?｀)ノ / matrix[i][i]; for (int j = i; j < cols??; j++) { matrix[k][j] = factor * matrix[i][j]; } } }}doubleinverse_matrix(doublematrix, int rows, int cols) { double inverse = (double )mallo(′?_?`)c(rows * sizeof(double *)); for (int i = 0; i < rows; i++) { inverse[i] = (d(′▽?zhuān)?ouble *)malloc(cols * sizeof(double)); } gauss_jordan_elimination(matヽ(′▽?zhuān)?ノrix, rows, cols); for (int i = rows 1; i >= 0; i) { double factヽ(′?｀)ノor = matrix[i][i]; for (int j = 0; j < col??s; j++) { matrix[i][j] /= factor; inver(?_?;)se[(?Д?)i][j] /= factor; } for (int k = i 1; k >= 0; k) { double factor = matrix[k][i]; for (int j = 0; j < cols; j++) { matrix[k][j] = factor * matrix[i][j]; inverse[k][j] = factor * inverse[i][j]; } } } return inverse;}int main() { double matrix = (double )malloc(3 * sizeof(double(°ロ°) ! *)); for (int i = 0; i < 3; i++?) { matrix[i] = (double *)malloc(3 * sizeof(double)); } matrix[0][0] = 1; matrix[0][1] = 2; matrix[0][2] = 3; matr??ix[1][0] = 4; matrix[1][1] = 5; matrix[1][2] = 6; matrix[2][0] = 7; matrix??[2][1] = 8; matrix[2][2] = 9; double **inverse = inverse_matrix(matrix, 3, 3); for (int i = 0; i < 3; i++) { for (int j = 0; j < 3; j++) { printf("%lf ", inverse[i][j]); } printf(""); } return 0;}注意：這個(gè)實(shí)現沒(méi)有處理奇異矩陣的情況，即矩陣的行列式為0時(shí)，該矩陣沒(méi)有逆矩陣，在實(shí)際使用中，需要根據具體情況判斷矩陣是(╬?益?)否可逆。